When determining the percent increase from 110 to 440, what is necessary to check first?

When determining the percent increase from 110 to 440, what is necessary to check first?

• A. Conversion of the numbers
• B. If the change is increasing or decreasing
• C. Finding the average
• D. Calculating the total

Answer: (B)

To determine the percent increase from 110 to 440, it is essential first to establish if the change is increasing or decreasing. In this scenario, since we are comparing 110 to 440, we see that the value is indeed increasing. Understanding the nature of the change informs how to proceed with the calculation. The next step would involve calculating the actual increase, which is derived from subtracting the initial value from the final value (440 - 110). This step illustrates that there was an increase, making it clear that a percent increase calculation will be applied. Thus, identifying the change as an increase helps lay the groundwork for the subsequent calculations that will determine the percentage increase. In summary, confirming whether the change is increasing or decreasing is a foundational step in solving the percent increase problem effectively.

To determine the percent increase from 110 to 440, it is essential first to establish if the change is increasing or decreasing. In this scenario, since we are comparing 110 to 440, we see that the value is indeed increasing.

Understanding the nature of the change informs how to proceed with the calculation. The next step would involve calculating the actual increase, which is derived from subtracting the initial value from the final value (440 - 110). This step illustrates that there was an increase, making it clear that a percent increase calculation will be applied. Thus, identifying the change as an increase helps lay the groundwork for the subsequent calculations that will determine the percentage increase.

In summary, confirming whether the change is increasing or decreasing is a foundational step in solving the percent increase problem effectively.